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9y^2-76y+160=0
a = 9; b = -76; c = +160;
Δ = b2-4ac
Δ = -762-4·9·160
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-76)-4}{2*9}=\frac{72}{18} =4 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-76)+4}{2*9}=\frac{80}{18} =4+4/9 $
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